Homework For Lab 6 Gravitational Forces Answers

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planetorganic

Nov 12, 2025 · 12 min read

Homework For Lab 6 Gravitational Forces Answers
Homework For Lab 6 Gravitational Forces Answers

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    Gravitational forces, the invisible threads that bind celestial bodies and dictate the motion of objects on Earth, are a cornerstone of physics. Understanding these forces is crucial, and often, homework assignments, such as those for Lab 6, are designed to solidify this knowledge. Let's dive into the intricacies of gravitational forces, exploring common concepts, calculations, and the potential answers you might encounter in such an assignment.

    Understanding Gravitational Forces: A Foundation

    Before tackling the specific questions in Lab 6, it's essential to grasp the fundamental principles that govern gravitational interactions.

    • Newton's Law of Universal Gravitation: This is the bedrock of understanding gravitational forces. It states that every particle of matter in the universe attracts every other particle with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. Mathematically, this is expressed as:

      • F = Gm₁m₂/r²

      • Where:

        • F is the gravitational force between the two objects.
        • G is the gravitational constant (approximately 6.674 × 10⁻¹¹ N⋅m²/kg²).
        • m₁ and m₂ are the masses of the two objects.
        • r is the distance between the centers of the two objects.
    • Gravitational Field: A gravitational field is a region of space around a massive object in which another object will experience a gravitational force. The strength of the gravitational field is defined as the gravitational force per unit mass.

    • Weight vs. Mass: While often used interchangeably in everyday language, weight and mass are distinct concepts in physics. Mass is a measure of the amount of matter in an object and is a scalar quantity. Weight, on the other hand, is the force of gravity acting on an object and is a vector quantity. Weight is calculated as:

      • W = mg

      • Where:

        • W is the weight of the object.
        • m is the mass of the object.
        • g is the acceleration due to gravity (approximately 9.8 m/s² on Earth's surface).
    • Superposition Principle: When dealing with multiple gravitational forces acting on a single object, the net gravitational force is the vector sum of all the individual forces. This is known as the superposition principle.

    Common Types of Homework Questions in Lab 6

    Lab 6 assignments focusing on gravitational forces typically involve a variety of question types designed to assess your understanding of the principles outlined above. Here's a breakdown of some common categories and examples, along with guidance on how to approach them.

    1. Calculating Gravitational Force

    These questions require direct application of Newton's Law of Universal Gravitation. You'll be given the masses of two objects and the distance between them, and asked to calculate the gravitational force.

    • Example: Two spheres, one with a mass of 5 kg and the other with a mass of 10 kg, are placed 2 meters apart. Calculate the gravitational force between them.

    • Solution:

      1. Identify the given values: m₁ = 5 kg, m₂ = 10 kg, r = 2 m, G = 6.674 × 10⁻¹¹ N⋅m²/kg².
      2. Plug the values into the formula: F = (6.674 × 10⁻¹¹ N⋅m²/kg²) * (5 kg) * (10 kg) / (2 m)²
      3. Calculate: F ≈ 8.34 × 10⁻¹⁰ N
      • Answer: The gravitational force between the spheres is approximately 8.34 × 10⁻¹⁰ N.

    2. Determining Weight

    These questions involve calculating the weight of an object given its mass and the acceleration due to gravity.

    • Example: A book has a mass of 1.5 kg. What is its weight on Earth?

    • Solution:

      1. Identify the given values: m = 1.5 kg, g = 9.8 m/s²
      2. Plug the values into the formula: W = (1.5 kg) * (9.8 m/s²)
      3. Calculate: W = 14.7 N
      • Answer: The book's weight on Earth is 14.7 N.

    3. Comparing Gravitational Forces

    These questions often ask you to compare the gravitational force between two different pairs of objects or to analyze how changing the mass or distance affects the force.

    • Example: How does the gravitational force between two objects change if the distance between them is doubled?

    • Solution:

      • According to Newton's Law of Universal Gravitation (F = Gm₁m₂/r²), the gravitational force is inversely proportional to the square of the distance. Therefore, if the distance (r) is doubled, the force becomes:

        • F' = Gm₁m₂/(2r)² = Gm₁m₂/4r² = (1/4) * (Gm₁m₂/r²) = (1/4) * F
      • Answer: The gravitational force is reduced to one-quarter of its original value.

    4. Gravitational Fields

    These questions may involve calculating the gravitational field strength at a certain distance from a massive object.

    • Example: Calculate the gravitational field strength at the surface of the Earth. (Mass of Earth = 5.972 × 10²⁴ kg, Radius of Earth = 6.371 × 10⁶ m)

    • Solution:

      1. The gravitational field strength (g) is the same as the acceleration due to gravity. We can calculate it using Newton's Law of Universal Gravitation, considering a small mass m on the surface of the Earth:

        • F = GmMe/Re² where Me is the mass of Earth and Re is the radius of Earth.
      2. Since F = mg, we can write: mg = GmMe/Re²

      3. Solving for g: g = GMe/Re²

      4. Plug in the values: g = (6.674 × 10⁻¹¹ N⋅m²/kg²) * (5.972 × 10²⁴ kg) / (6.371 × 10⁶ m)²

      5. Calculate: g ≈ 9.81 m/s²

      • Answer: The gravitational field strength at the surface of the Earth is approximately 9.81 m/s².

    5. Superposition of Gravitational Forces

    These questions involve scenarios where multiple objects exert gravitational forces on a single object. You'll need to calculate the individual forces and then find their vector sum.

    • Example: Three objects are arranged in a straight line. Object A has a mass of 2 kg and is located at x = 0 m. Object B has a mass of 3 kg and is located at x = 2 m. Object C has a mass of 5 kg and is located at x = 5 m. What is the net gravitational force on object A due to objects B and C?

    • Solution:

      1. Calculate the gravitational force between A and B (FAB):

        • FAB = G * mA * mB / rAB² = (6.674 × 10⁻¹¹ N⋅m²/kg²) * (2 kg) * (3 kg) / (2 m)² ≈ 1.00 × 10⁻¹⁰ N. This force is directed towards object B (positive x-direction).
      2. Calculate the gravitational force between A and C (FAC):

        • FAC = G * mA * mC / rAC² = (6.674 × 10⁻¹¹ N⋅m²/kg²) * (2 kg) * (5 kg) / (5 m)² ≈ 0.27 × 10⁻¹⁰ N. This force is directed towards object C (positive x-direction).
      3. Find the net force by adding the forces vectorially: Since both forces are in the same direction, we simply add their magnitudes.

        • Fnet = FAB + FAC = 1.00 × 10⁻¹⁰ N + 0.27 × 10⁻¹⁰ N ≈ 1.27 × 10⁻¹⁰ N
      • Answer: The net gravitational force on object A is approximately 1.27 × 10⁻¹⁰ N in the positive x-direction.

    6. Conceptual Questions

    These questions test your understanding of the underlying principles of gravitational forces without requiring calculations.

    • Example: Explain why objects with different masses fall at the same rate in a vacuum.

    • Solution:

      • The acceleration due to gravity is independent of the mass of the falling object. While the gravitational force on a more massive object is greater (F = mg), its inertia (resistance to acceleration) is also greater. These two effects cancel each other out, resulting in the same acceleration for all objects in the absence of air resistance. This can be derived from Newton's Second Law (F=ma) and the Law of Universal Gravitation (F = Gm₁m₂/r²). Setting these equal to each other (mg = GmMe/Re²) and solving for the acceleration (a, which becomes g), we see that g = GMe/Re², which is independent of the mass of the falling object (m).

    Strategies for Solving Homework Problems

    Here are some useful strategies to help you successfully complete your Lab 6 homework:

    • Understand the Concepts: Before attempting any problems, make sure you have a solid understanding of the underlying principles, including Newton's Law of Universal Gravitation, gravitational fields, weight, and mass.

    • Draw Diagrams: For problems involving multiple objects or complex scenarios, drawing a diagram can help you visualize the situation and identify the relevant forces and distances.

    • Organize Your Work: Write down all the given information and the quantity you are trying to find. This will help you stay organized and avoid mistakes.

    • Use the Correct Units: Ensure that all quantities are expressed in consistent units (e.g., kilograms for mass, meters for distance, and seconds for time). If necessary, convert units before plugging them into the formulas.

    • Show Your Work: Clearly show all the steps involved in your calculations. This will allow you (and your instructor) to identify any errors you may have made.

    • Check Your Answer: After you have obtained an answer, check to see if it is reasonable. For example, if you are calculating the gravitational force between two objects on Earth, the answer should be a very small number.

    Common Mistakes to Avoid

    • Forgetting to Square the Distance: A very common mistake is forgetting to square the distance (r) in Newton's Law of Universal Gravitation.

    • Using Incorrect Units: Always double-check that you are using the correct units for all quantities.

    • Confusing Weight and Mass: Remember that weight is a force and mass is a measure of the amount of matter. They are related by the equation W = mg.

    • Incorrect Vector Addition: When dealing with multiple gravitational forces, be sure to add them vectorially, taking into account their directions.

    • Not Understanding the Concepts: Trying to solve problems without a solid understanding of the underlying principles will often lead to mistakes.

    Advanced Considerations (Beyond Basic Lab 6)

    While Lab 6 focuses on basic gravitational force calculations, it's worth noting some more advanced concepts related to gravity that you might encounter later in your physics studies:

    • General Relativity: Einstein's theory of general relativity provides a more accurate description of gravity than Newton's law, especially in strong gravitational fields or at very high speeds. General relativity describes gravity not as a force, but as a curvature of spacetime caused by mass and energy.

    • Tidal Forces: These are differential gravitational forces that occur when the gravitational force on one side of an object is significantly different from the gravitational force on the other side. Tidal forces are responsible for the tides on Earth, caused by the Moon's gravity.

    • Gravitational Potential Energy: This is the potential energy that an object has due to its position in a gravitational field. It is the energy required to move an object from a point in space to a reference point (usually infinity) against the force of gravity.

    • Dark Matter and Dark Energy: These are mysterious substances that make up the vast majority of the universe's mass and energy. Their existence is inferred from their gravitational effects on visible matter and the expansion of the universe.

    Example Problems and Detailed Solutions

    Let's work through a couple more example problems with detailed solutions to solidify your understanding.

    Problem 1:

    A satellite with a mass of 500 kg orbits the Earth at an altitude of 500 km above the Earth's surface. Calculate the gravitational force between the Earth and the satellite. (Mass of Earth = 5.972 × 10²⁴ kg, Radius of Earth = 6.371 × 10⁶ m)

    Solution:

    1. Identify the given values:

      • m₁ (mass of satellite) = 500 kg
      • m₂ (mass of Earth) = 5.972 × 10²⁴ kg
      • Altitude = 500 km = 500,000 m
      • Radius of Earth (Re) = 6.371 × 10⁶ m
      • G = 6.674 × 10⁻¹¹ N⋅m²/kg²
    2. Calculate the distance (r) between the centers of the Earth and the satellite:

      • r = Re + Altitude = 6.371 × 10⁶ m + 500 × 10³ m = 6.871 × 10⁶ m
    3. Apply Newton's Law of Universal Gravitation:

      • F = Gm₁m₂/r² = (6.674 × 10⁻¹¹ N⋅m²/kg²) * (500 kg) * (5.972 × 10²⁴ kg) / (6.871 × 10⁶ m)²
    4. Calculate:

      • F ≈ 4229 N

    Answer: The gravitational force between the Earth and the satellite is approximately 4229 N.

    Problem 2:

    Two asteroids, A and B, are located in space. Asteroid A has a mass of 2.0 × 10¹⁰ kg, and Asteroid B has a mass of 5.0 × 10¹⁰ kg. They are separated by a distance of 1.0 × 10⁶ m.

    a) Calculate the gravitational force between the two asteroids.

    b) If a small probe with a mass of 100 kg is placed exactly halfway between the two asteroids, what is the net gravitational force on the probe?

    Solution:

    a) Calculate the gravitational force between A and B (FAB):

    1. Identify the given values:

      • mA (mass of Asteroid A) = 2.0 × 10¹⁰ kg
      • mB (mass of Asteroid B) = 5.0 × 10¹⁰ kg
      • rAB (distance between A and B) = 1.0 × 10⁶ m
      • G = 6.674 × 10⁻¹¹ N⋅m²/kg²
    2. Apply Newton's Law of Universal Gravitation:

      • FAB = GmAmB/rAB² = (6.674 × 10⁻¹¹ N⋅m²/kg²) * (2.0 × 10¹⁰ kg) * (5.0 × 10¹⁰ kg) / (1.0 × 10⁶ m)²
    3. Calculate:

      • FAB ≈ 6.674 × 10⁻³ N

    Answer (a): The gravitational force between the two asteroids is approximately 6.674 × 10⁻³ N.

    b) Calculate the net gravitational force on the probe:

    1. Identify the given values:

      • mP (mass of the probe) = 100 kg
      • rAP (distance between Asteroid A and the probe) = 0.5 × 10⁶ m (half the distance between A and B)
      • rBP (distance between Asteroid B and the probe) = 0.5 × 10⁶ m (half the distance between A and B)
    2. Calculate the gravitational force between Asteroid A and the probe (FAP):

      • FAP = GmAmP/rAP² = (6.674 × 10⁻¹¹ N⋅m²/kg²) * (2.0 × 10¹⁰ kg) * (100 kg) / (0.5 × 10⁶ m)²
      • FAP ≈ 5.339 × 10⁻⁶ N. This force is directed towards Asteroid A.
    3. Calculate the gravitational force between Asteroid B and the probe (FBP):

      • FBP = GmBmP/rBP² = (6.674 × 10⁻¹¹ N⋅m²/kg²) * (5.0 × 10¹⁰ kg) * (100 kg) / (0.5 × 10⁶ m)²
      • FBP ≈ 1.335 × 10⁻⁵ N. This force is directed towards Asteroid B.
    4. Find the net force: Since the forces are in opposite directions, we subtract their magnitudes. We'll consider the direction towards Asteroid B to be positive.

      • Fnet = FBP - FAP = 1.335 × 10⁻⁵ N - 5.339 × 10⁻⁶ N ≈ 8.011 × 10⁻⁶ N

    Answer (b): The net gravitational force on the probe is approximately 8.011 × 10⁻⁶ N, directed towards Asteroid B.

    Conclusion

    Mastering gravitational forces is essential for a solid understanding of physics. By grasping the fundamental principles, practicing problem-solving techniques, and avoiding common mistakes, you can successfully tackle your Lab 6 homework and build a strong foundation for future studies in physics and related fields. Remember to focus on understanding the concepts, organizing your work, and checking your answers to ensure accuracy. Good luck!

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